document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329389>Question 329389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ways can a 4-person subcommittee be selected from a committee of 9 people? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236126 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 1st picked is 1 of 9, then 1 of 8, 7, & 6.<BR>\n" );
document.write( "= 9*8*7*6 = 3024<BR>\n" );
document.write( "But, ABCD is the same as BDCA, so divide by 4*3*2*1 = 24<BR>\n" );
document.write( "--> 3024/24 = 126 different ways<BR>\n" );
document.write( " </SPAN>\n" );
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