document.write( "Question 329416: A carpenter is building a rectangle room with a fixed perimeter of 356 ft. What dimensions would yield the maximum area? \r
\n" ); document.write( "\n" ); document.write( "What is the maximum area?
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Algebra.Com's Answer #236106 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
THe perimeter of a rectangle is,
\n" ); document.write( "\"P=2L%2B2W=356\"
\n" ); document.write( "\"L%2BW=178\"
\n" ); document.write( "The area of a rectangle is,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "From the perimeter equation,
\n" ); document.write( "\"L=178-W\"
\n" ); document.write( "Substitute into the area equation,
\n" ); document.write( "\"A=%28178-W%29W\"
\n" ); document.write( "Now the area is a function of one variable.
\n" ); document.write( "To find the maximum, take the derivative wrt W and set it equal to zero.
\n" ); document.write( "\"A=178W-W%5E2\"
\n" ); document.write( "\"dA%2FdW=178-2W=0\"
\n" ); document.write( "\"2W=178\"
\n" ); document.write( "\"W=89\"
\n" ); document.write( "Then from above,
\n" ); document.write( "\"L=178-89=89\"
\n" ); document.write( "The maximum area for a given perimeter is obtained using a square.
\n" ); document.write( "\"Amax=89%5E2=7921\"sq.ft.
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