document.write( "Question 329369: train A and B are traveling in the same direction on parallel tracks. Train A IS TRAVELING 60 MILES PER HOUR AND TRAIN B IS TRAVELING AT 70 MILES PER HOUR. TRAIN A PASSES A STATION AT 4:10 A.M. IF TRAIN B PASSES THE SAME STATION AT 4:22 A.M. AT WHAT TIME WILL TRAIN B CATCH UP WITH TRAIN A? \n" ); document.write( "
Algebra.Com's Answer #236102 by mananth(16946) You can put this solution on YOUR website! there are two methods of working \n" ); document.write( ".. \n" ); document.write( "speed of train A = 60 mph \n" ); document.write( "speed of train B = 70 mph \n" ); document.write( ".. \n" ); document.write( "train B passes 12 minutes later than Train A \n" ); document.write( "so Train A has traveled 12/60*60 miles = 12 miles in 12 minutes. \n" ); document.write( ".. \n" ); document.write( "Let train B catch up with train A after x miles \n" ); document.write( "time taken = x/70 \n" ); document.write( ".. \n" ); document.write( "meanwhile train A travels x-12/60 \n" ); document.write( ".. \n" ); document.write( "(x-12)/60 = x/70 \n" ); document.write( "70(x-12)=60x \n" ); document.write( "70x-840=60x \n" ); document.write( "70x-60x=840 \n" ); document.write( "10x=840 \n" ); document.write( "x= 84 miles \n" ); document.write( "speed of train B = 70 mph \n" ); document.write( "time = 84/70 \n" ); document.write( "=1.2 hours OR 72 minutes \n" ); document.write( "Train B will catch up after 72 minutes at 5.34 pm \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "train B covers 10 miles extra per hour. \n" ); document.write( "train b has traveled 12 miles \n" ); document.write( "to catch up it will take 12/10 hours = 1.2 hours = 72 minutes. ( so simple) \n" ); document.write( " |