document.write( "Question 329369: train A and B are traveling in the same direction on parallel tracks. Train A IS TRAVELING 60 MILES PER HOUR AND TRAIN B IS TRAVELING AT 70 MILES PER HOUR. TRAIN A PASSES A STATION AT 4:10 A.M. IF TRAIN B PASSES THE SAME STATION AT 4:22 A.M. AT WHAT TIME WILL TRAIN B CATCH UP WITH TRAIN A? \n" ); document.write( "
Algebra.Com's Answer #236102 by mananth(16946)\"\" \"About 
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there are two methods of working
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\n" ); document.write( "speed of train A = 60 mph
\n" ); document.write( "speed of train B = 70 mph
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\n" ); document.write( "train B passes 12 minutes later than Train A
\n" ); document.write( "so Train A has traveled 12/60*60 miles = 12 miles in 12 minutes.
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\n" ); document.write( "Let train B catch up with train A after x miles
\n" ); document.write( "time taken = x/70
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\n" ); document.write( "meanwhile train A travels x-12/60
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\n" ); document.write( "(x-12)/60 = x/70
\n" ); document.write( "70(x-12)=60x
\n" ); document.write( "70x-840=60x
\n" ); document.write( "70x-60x=840
\n" ); document.write( "10x=840
\n" ); document.write( "x= 84 miles
\n" ); document.write( "speed of train B = 70 mph
\n" ); document.write( "time = 84/70
\n" ); document.write( "=1.2 hours OR 72 minutes
\n" ); document.write( "Train B will catch up after 72 minutes at 5.34 pm
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\n" ); document.write( "\n" ); document.write( "train B covers 10 miles extra per hour.
\n" ); document.write( "train b has traveled 12 miles
\n" ); document.write( "to catch up it will take 12/10 hours = 1.2 hours = 72 minutes. ( so simple)
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