document.write( "Question 329404: A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The length of a side of the square is thirty feet. Which equations would help you solve for the dimensions of the rectangle?
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document.write( "What are the dimensions of the rectangle?\r
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document.write( "I really need help on this any help is appreciated !!! \n" );
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Algebra.Com's Answer #236085 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width of rectangle be x \n" ); document.write( "length will be 2x+70 \n" ); document.write( "Area of rectangle = length * width \n" ); document.write( "=x(2x+70) \n" ); document.write( ".. \n" ); document.write( "Area of square = L^2 \n" ); document.write( "L= 30 \n" ); document.write( "area = 30^2= 900 \n" ); document.write( ".. \n" ); document.write( "But the area of square = area of rectangle \n" ); document.write( "x(2x+70)=900 \n" ); document.write( "2x^2+70x=900 \n" ); document.write( "divide by 2 \n" ); document.write( "x^2+35x=450 \n" ); document.write( "x^2+35x-450=0 \n" ); document.write( "x^2+45x-10x-450=0 \n" ); document.write( "x(x+45)-10(x+45)=0 \n" ); document.write( "(x+45)(x-10)=0 \n" ); document.write( "x=-45 OR x=10 \n" ); document.write( "ignore the negative value \n" ); document.write( "width = 10 \n" ); document.write( "Length = 2x +70 \n" ); document.write( "= 2*10+70= 90 feet length \n" ); document.write( "CHECK \n" ); document.write( "AREA = 90*10 =900 square feet \n" ); document.write( " |