document.write( "Question 329404: A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The length of a side of the square is thirty feet. Which equations would help you solve for the dimensions of the rectangle?
\n" ); document.write( "What are the dimensions of the rectangle?\r
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\n" ); document.write( "\n" ); document.write( "I really need help on this any help is appreciated !!!
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Algebra.Com's Answer #236085 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let width of rectangle be x
\n" ); document.write( "length will be 2x+70
\n" ); document.write( "Area of rectangle = length * width
\n" ); document.write( "=x(2x+70)
\n" ); document.write( "..
\n" ); document.write( "Area of square = L^2
\n" ); document.write( "L= 30
\n" ); document.write( "area = 30^2= 900
\n" ); document.write( "..
\n" ); document.write( "But the area of square = area of rectangle
\n" ); document.write( "x(2x+70)=900
\n" ); document.write( "2x^2+70x=900
\n" ); document.write( "divide by 2
\n" ); document.write( "x^2+35x=450
\n" ); document.write( "x^2+35x-450=0
\n" ); document.write( "x^2+45x-10x-450=0
\n" ); document.write( "x(x+45)-10(x+45)=0
\n" ); document.write( "(x+45)(x-10)=0
\n" ); document.write( "x=-45 OR x=10
\n" ); document.write( "ignore the negative value
\n" ); document.write( "width = 10
\n" ); document.write( "Length = 2x +70
\n" ); document.write( "= 2*10+70= 90 feet length
\n" ); document.write( "CHECK
\n" ); document.write( "AREA = 90*10 =900 square feet
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