document.write( "Question 329395: The side of a large tent is in the shape of an isosceled triangle whose area is 54ft^2 and whose base is 6 ft shorter than twice its height. Find the height and the base of the side of the tent. \n" ); document.write( "
Algebra.Com's Answer #236080 by mananth(16946)\"\" \"About 
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let height be x
\n" ); document.write( "base = 2x-6
\n" ); document.write( "Area = 54
\n" ); document.write( "..
\n" ); document.write( "Area of triangle = 1/2 * base * height
\n" ); document.write( "54=1/2 * x*(2x-6)
\n" ); document.write( "2*54=x(2x-6)
\n" ); document.write( "108=2x^2-6x
\n" ); document.write( "2x^2-6x-108=0
\n" ); document.write( "divide by 2
\n" ); document.write( "x^2-3x-54=0
\n" ); document.write( "x^2-9x+6x-54=0
\n" ); document.write( "x(x-9)+6(x-9)=0
\n" ); document.write( "(x-9)(x+6)=0
\n" ); document.write( "x=9 OR x =-6 ignore the negative value
\n" ); document.write( "So x=9 feet height
\n" ); document.write( "base = 2x-6
\n" ); document.write( "base = 2*9-6
\n" ); document.write( "base = 18-6
\n" ); document.write( "base = 12 feet.
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