document.write( "Question 329349: Dave and his son can do a job in 4 1/2 days. After they have worked for 3 days, Dave got sick, and the son finished the task in 6 more days. How many days each is required to do the entire task? \n" ); document.write( "
Algebra.Com's Answer #236041 by scott8148(6628)\"\" \"About 
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in the 3 days they worked together , they completed 2/3 of the job (3 / 4 1/2)\r
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\n" ); document.write( "\n" ); document.write( "so the son took 6 days to do 1/3 of the job ___ it would take him 18 days to do the job by himself\r
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\n" ); document.write( "\n" ); document.write( "in 4 1/2 days , the son does 1/4 of the job (4 1/2 / 18)\r
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\n" ); document.write( "\n" ); document.write( "so Dave does 3/4 of the job in 4 1/2 days ___ it would take him 6 days to do the job by himself (4 1/2 / 3/4)
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