document.write( "Question 329320: Looking for assistance in creating an equation to solve the following problem.\r
\n" ); document.write( "\n" ); document.write( "The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph?
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Algebra.Com's Answer #236022 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Ok, here's the equation:
\n" ); document.write( "Let F = Force required to keep car from skidding.
\n" ); document.write( "Let W = Weight of car in lbs.
\n" ); document.write( "Let S = Speed of car in mph.
\n" ); document.write( "Let r = Radius of the curve in feet.
\n" ); document.write( "Let k = the constant of variation.
\n" ); document.write( "\"F+=+%28W%2A%28S%29%5E2%2Fr%29%2Ak\" First, find the value of k. Substitute the given values of: F = 3600 lbs, W = 1800 lbs, S = 20 mph, and r = 600 ft.
\n" ); document.write( "\"3600+=+%281800%2820%29%5E2%2F600%29%2Ak\" Evaluate.
\n" ); document.write( "\"3600+=+%28%281800%2A400%29%2F600%29%2Ak\"
\n" ); document.write( "\"3600+=+%281200%29%2Ak\"
\n" ); document.write( "\"k+=+3\" Now thw equation becomes:
\n" ); document.write( "\"F+=+%28W%2A%28S%29%5E2%2Fr%29%2A3\" Now substitute the problem values of: W = 1800 lbs, S = 50 mph, and r = 570 ft.
\n" ); document.write( "You can work this out.
\n" ); document.write( "I got F = 23,684.2 lbs.
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