document.write( "Question 329143: solve the system\r
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Algebra.Com's Answer #235979 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Rules for solving a system of three equations in three unknowns:\r\n" );
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document.write( "1. If one of the equations has only two unknowns, call it \"equation 1\".\r\n" );
document.write( "Observe which of the three unknowns is missing from that equation and \r\n" );
document.write( "eliminate that unknown from the other two equations, and call the \r\n" );
document.write( "resulting equation \"equation 2\".\r\n" );
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document.write( "2. If all three equations contain all three unknowns, pick two of the \r\n" );
document.write( "three equations and eliminate an unknown from them, and call the \r\n" );
document.write( "resulting equation \"equation 1\".  Us the eqution you haven't yet used with \r\n" );
document.write( "one of the others and eliminate that same letter.  Call the resulting \r\n" );
document.write( "equation \"equation 2\".\r\n" );
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document.write( "3. Solve the system of two equation in two unknowns, consisting of \"equation\r\n" );
document.write( "1\" and \"equation 2\".\r\n" );
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document.write( "4. Find the third unknown by substituting in one of the original equations \r\n" );
document.write( "that contains that third unknown.\r\n" );
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document.write( "\"syatem%28z-3y=1%2C+x%2By%2Bz=3%2C+x%2B5y=3%29\"\r\n" );
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document.write( "Step 1.  One of the equations has only two unknowns, in fact two of them\r\n" );
document.write( "do.  I'll pick the first one \"z-3y=1\" and call it \"equation 1\"\r\n" );
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document.write( "I observe that the unknown x is missing from \"equation 1\" and \r\n" );
document.write( "so I'll eliminate x from the other two equations:\r\n" );
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document.write( "\"x%2By%2Bz=3\"\r\n" );
document.write( "\"x%2B5y=3\"\r\n" );
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document.write( "To eliminate the x's we multiply one of them, say the first, by -1\r\n" );
document.write( "to make the x's cancel when I add them term by term:\r\n" );
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document.write( "\"x%2By%2Bz=3\"\r\n" );
document.write( "\"-x-5y=-3\"\r\n" );
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document.write( "Result:\r\n" );
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document.write( "\"-4y%2Bz=0\", that's \"equation 2\".\r\n" );
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document.write( "Now we solve the system consisting of equation 1 and equation 2:\r\n" );
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document.write( "\"system%28z-3y=1%2C%0D%0A-4y%2Bz=0%29\"\r\n" );
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document.write( "Swap the two terms on the left of the first one so the unknowns\r\n" );
document.write( "will be in the same order:\r\n" );
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document.write( "\"system%28-3y%2Bz=1%2C%0D%0A-4y%2Bz=0%29\"\r\n" );
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document.write( "To make the z's cancel when we add them term by term, we multiply the \r\n" );
document.write( "first one through by -1:\r\n" );
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document.write( "\"system%283y-z=-1%2C%0D%0A-4y%2Bz=0%29\" \r\n" );
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document.write( "Result:\r\n" );
document.write( "\"-y=-1\"\r\n" );
document.write( "\"y=1\"\r\n" );
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document.write( "Substitute that in \r\n" );
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document.write( "\"-3y%2Bz=1\"\r\n" );
document.write( "\"-3%281%29%2Bz=1\"\r\n" );
document.write( "\"-3%2Bz=1\"\r\n" );
document.write( "\"z=4\"\r\n" );
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document.write( "Substitute those in the original equation  \"x%2B5y=3\"\r\n" );
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document.write( "\"x%2B5%281%29=3\"\r\n" );
document.write( "\"x%2B5=3\"\r\n" );
document.write( "\"x=-2\"\r\n" );
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document.write( "Solution: \"%22%28x%2Cy%2Cz%29%22\"\"%22%22=%22%22\"\"%22%28-2%2C1%2C4%29%22\"\r\n" );
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document.write( "Edwin
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