document.write( "Question 329209: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
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Algebra.Com's Answer #235916 by Fombitz(32388) $\"\"$ $\"About$

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Rate*Time=Distance
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\n" ); document.write( "During the 3 hours, the first cyclist travels 3(6)=18 miles.
\n" ); document.write( " $\"D1=18%2B6t\"$
\n" ); document.write( " $\"D2=10t\"$
\n" ); document.write( "Find t when D1=D2.
\n" ); document.write( " $\"18%2B6t=10t\"$
\n" ); document.write( " $\"4t=18\"$
\n" ); document.write( " $\"t=9%2F2=4.25\"$
\n" ); document.write( "THey will meet in 4 hr 15 min. \n" ); document.write( "

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