document.write( "Question 329179: Solve each system by substitution\r
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document.write( "x/6 + y/10= 3\r
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document.write( "5x/16 - 3y/16= 15/8\r
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document.write( "/ are fractions. Sorry.\r
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document.write( "I know the answer is 12,10. Can you show me how to get that? \n" );
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Algebra.Com's Answer #235886 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve each system by substitution \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Get rid of those annoying fractions \n" ); document.write( ": \n" ); document.write( "Mult 1st equation by 30, results: \n" ); document.write( "5x + 3y = 90 \n" ); document.write( "3y = 90 - 5x \n" ); document.write( "divide thru by 3 \n" ); document.write( "y = 30 - \n" ); document.write( ": \n" ); document.write( "Mult 2nd equation by 16, results \n" ); document.write( "5x - 3y = 2(15) \n" ); document.write( "5x - 3y = 30 \n" ); document.write( "Substitute for y \n" ); document.write( "5x - 3(30 - \n" ); document.write( "5x - 90 + 5x = 30 \n" ); document.write( "5x + 5x = 30 + 90 \n" ); document.write( "10x = 120 \n" ); document.write( "x = 12 \n" ); document.write( ": \n" ); document.write( "Find y using eq: 5x - 3y = 30; replace x with 12 \n" ); document.write( "5(12) - 3y = 30 \n" ); document.write( "60 - 3y = 30 \n" ); document.write( "-3y = 30 - 60 \n" ); document.write( "-3y = -30 \n" ); document.write( "y = +10 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the first original equation \n" ); document.write( " \n" ); document.write( " |