document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4848>Question 4848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2358 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter = 2L+2W<BR>\n" );
document.write( "160=2L+2W<BR>\n" );
document.write( "Divide by 2<BR>\n" );
document.write( "80=L+W\r<BR>\n" );
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document.write( "Additionally we know that <BR>\n" );
document.write( "1/4L=2W<BR>\n" );
document.write( "Multiply by 4<BR>\n" );
document.write( "L=8W\r<BR>\n" );
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document.write( "So we can substitute that in:<BR>\n" );
document.write( "80=8W+W<BR>\n" );
document.write( "80=9W<BR>\n" );
document.write( "8.88=W\r<BR>\n" );
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document.write( "L=8W<BR>\n" );
document.write( "L=8(8.88)<BR>\n" );
document.write( "L=71.77\r<BR>\n" );
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document.write( "160=2(71.11)+2(8.88)\r<BR>\n" );
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document.write( "Pretty unusual numbers for this kind of math problem...\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );