document.write( "Question 329043: log₂(x+20)- log₂(x+2)= log₂x \n" ); document.write( "

Algebra.Com's Answer #235795 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%282%2C%28x%2B20%29%29-+log%282%2C%28x%2B2%29%29=+log%282%2C%28x%29%29\"$
\n" ); document.write( " $\"log%282%2C%28%28x%2B20%29%2F%28x%2B2%29%29%29=+log%282%2C%28x%29%29\"$
\n" ); document.write( " $\"%28x%2B20%29%2F%28x%2B2%29=+x\"$
\n" ); document.write( " $\"x%2B20=x%28x%2B2%29\"$
\n" ); document.write( " $\"x%2B20=x%5E2%2B2x\"$
\n" ); document.write( " $\"x%5E2%2Bx-20=0\"$
\n" ); document.write( " $\"%28x%2B5%29%28x-4%29=0\"$
\n" ); document.write( "Only a positive solution is allowed since the log function requires a positive argument.
\n" ); document.write( " $\"x-4=0\"$
\n" ); document.write( " $\"highlight%28x=4%29\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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