document.write( "Question 329074: My test scores are75,90,77,88, out of 100. What should my fifth grade so that the average is at least 83? \n" ); document.write( "
Algebra.Com's Answer #235783 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Your total score now is 75 + 90 + 77 + 88 = 330 \n" ); document.write( "You have 4 scores. \n" ); document.write( "Add one more score and you'll have 5 scores. \n" ); document.write( "Divide that by 5 and you'll get the new average. \n" ); document.write( "You want the new average to be >= 83.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the fifth score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your formula is (330 + x) / 5 >= 83\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This will give you 5 scores that, divided by 5, will give you an average that is greater than or equal to 83.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides of that equation by 5 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "330 + x >= 83 * 5 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "330 + x >= 415\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 330 from both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x >= 415 - 330 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x >= 85.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to get 85 or more to have an overall average of 83.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your old total is 330.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 85 to it to get a new total of 415.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide 415 by 5 and you get an average of 85.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |