document.write( "Question 329077: A rectangular garden is to be surrounded by a walkway of constant width. The gardens dimensions are 24ft by 26 ft. The total area garden plus walkway is to be 1129ft^2. What must be the width of the walkway? round to the nearest thousandth if necessary.\r
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Algebra.Com's Answer #235773 by mananth(16946)\"\" \"About 
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24 by 26 feet sre the dimensions of the garden
\n" ); document.write( "let x be the width of walkway.
\n" ); document.write( "the length of plot will be 26+2x
\n" ); document.write( "width of plot will be 24+2x
\n" ); document.write( "Area of plot = (24+2x)(26+2x)=1129
\n" ); document.write( "624+48x+52x+4x^2=1129
\n" ); document.write( "4x^2+100x+624-1129=0
\n" ); document.write( "4x^2+100x-505=0
\n" ); document.write( "solve using quadratic equation
\n" ); document.write( "a=4, b=100, c=-505
\n" ); document.write( "x1= (-100+sqrt(100^2+(16*505)))/ (2*4)
\n" ); document.write( "=4.308
\n" ); document.write( "x2= (-100-sqrt(100^2+(16*505)))/ (2*4)
\n" ); document.write( "x2=-29.3 ignore this value.\r
\n" ); document.write( "\n" ); document.write( "The width will be 4.308 feet
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