document.write( "Question 329023: Working together, Fred and Jill can feed the chickens in 4 hours. Working alone, Jill can feed the chickens in 10 hours. How long would it take Fred to feed the chickens working by himself? \n" ); document.write( "
Algebra.Com's Answer #235741 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Fred & jill together can do a job in 4 hours
\n" ); document.write( "so tthwy do 1/4 of the job in 1 hour
\n" ); document.write( "..
\n" ); document.write( "jill can do the job in 10 hours
\n" ); document.write( "she does 1/10 of the job in 1 hour
\n" ); document.write( "..
\n" ); document.write( "Fred will do 1/4 -1/10 of the job in 1 hour
\n" ); document.write( "LCD = 20
\n" ); document.write( "5-2 / 20 = 3/20
\n" ); document.write( "so fred can do the job alone in 20/3 hours
\n" ); document.write( "=6.66 hours
\n" ); document.write( "
\n" );