document.write( "Question 328847: Adam has $1.14 in change made up of pennies, nickels and dimes. He has 6 more nickels than pennies and 6 fewer dimes than pennies. How many of each coin does he have. \n" ); document.write( "
Algebra.Com's Answer #235705 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Write an equation for each statement
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\n" ); document.write( "Adam has $1.14 in change made up of pennies, nickels and dimes.
\n" ); document.write( ".01p + .05n + .10d = 1.14
\n" ); document.write( "get rid of the decimals, mult by 100
\n" ); document.write( "1p + 5n + 10d = 114
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\n" ); document.write( "He has 6 more nickels than pennies
\n" ); document.write( "n = p + 6
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\n" ); document.write( "6 fewer dimes than pennies.
\n" ); document.write( "d = p - 6
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\n" ); document.write( "How many of each coin does he have.
\n" ); document.write( "Everything in terms of p
\n" ); document.write( ":
\n" ); document.write( "Using the 1st equation replace n and d using the 2nd and 3rd equation
\n" ); document.write( "1p + 5(p+6) + 10(p-6) = 114
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\n" ); document.write( "p + 5p + 30 + 10p - 60 = 114
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\n" ); document.write( "16p - 30 = 114
\n" ); document.write( ":
\n" ); document.write( "16p = 114 + 30
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\n" ); document.write( "16p = 144
\n" ); document.write( "p = \"144%2F16\"
\n" ); document.write( "p = 9, pennies
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\n" ); document.write( "I'll let you find n and d, check solution in original 1st equation \n" ); document.write( "
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