document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328811>Question 328811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 42 inches. The second side is 1 inch more than twice the first side, and the third side is 1 inch less than three times the first  side. Find the lengths of the three side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235668 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p=a+b+c<BR>\n" );
document.write( "b=2a+1<BR>\n" );
document.write( "c=3a-1<BR>\n" );
document.write( "42=a+2a+1+3a-1<BR>\n" );
document.write( "42=6a<BR>\n" );
document.write( "6a=42<BR>\n" );
document.write( "a=42/6<BR>\n" );
document.write( "a=7 ans. for the first side.<BR>\n" );
document.write( "b=2*7+1=14+1=15 ans. for the second side.<BR>\n" );
document.write( "c=3*7-1=21-1=20 ans. for the third side.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "7+15+20=42<BR>\n" );
document.write( "42=42 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );