document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38065>Question 38065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and check for x.  Please help - I don't understand!\r<BR>\n" );
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document.write( "x/x-2 - x+1/x = 8/x^2-2x<BR>\n" );
document.write( "I had a hard time typing this in.  It is x over x-2 minus x+1 over x equals 8 over x squared minus 2x.  I hope that helps! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23565 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first step is to multiply everything by the lowest common denominator, which in this problem is (x^2 - 2x) or x(x - 2)...so from<BR>\n" );
document.write( "x / (x-2) - (x+1) / x = 8 / (x^2 - 2x)<BR>\n" );
document.write( "let's do just that...<BR>\n" );
document.write( "(x(x - 2))[x / (x - 2) - (x + 1) / x = 8 / (x^2 - 2x)]<BR>\n" );
document.write( "now cancel where you can and get<BR>\n" );
document.write( "x^2 - (x + 1)(x - 2) = 8<BR>\n" );
document.write( "Now expand, collect terms and solve<BR>\n" );
document.write( "x^2 - x^2 + x + 2 = 8<BR>\n" );
document.write( "x + 2 = 8<BR>\n" );
document.write( "x = 6 </SPAN>\n" );
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