document.write( "Question 328660: The square of one number is 23 less than the square of a second number. If the second number is 1 more than the first, what are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #235522 by mananth(16946)\"\" \"About 
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let one number be x
\n" ); document.write( "the other number be y
\n" ); document.write( "x^2=y^2-23
\n" ); document.write( "x^2-y^2=-23..............1
\n" ); document.write( "x+1=y
\n" ); document.write( "substitute the value of y in equation1
\n" ); document.write( "x^2-(x+1)^2=-23
\n" ); document.write( "x^2-x^-2x-1=-23
\n" ); document.write( "-2x=-23+1
\n" ); document.write( "-2x=-22
\n" ); document.write( "x=-22/-2
\n" ); document.write( "x=11
\n" ); document.write( "y= x+1
\n" ); document.write( "y=12
\n" ); document.write( "
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