document.write( "Question 328660: The square of one number is 23 less than the square of a second number. If the second number is 1 more than the first, what are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #235522 by mananth(16946) You can put this solution on YOUR website! let one number be x \n" ); document.write( "the other number be y \n" ); document.write( "x^2=y^2-23 \n" ); document.write( "x^2-y^2=-23..............1 \n" ); document.write( "x+1=y \n" ); document.write( "substitute the value of y in equation1 \n" ); document.write( "x^2-(x+1)^2=-23 \n" ); document.write( "x^2-x^-2x-1=-23 \n" ); document.write( "-2x=-23+1 \n" ); document.write( "-2x=-22 \n" ); document.write( "x=-22/-2 \n" ); document.write( "x=11 \n" ); document.write( "y= x+1 \n" ); document.write( "y=12 \n" ); document.write( " |