document.write( "Question 4850: Six apples and three oranges cost $3.36. Two apples and five oranges cost $3.04. Find the cost of an apple and the cost of an orange. \n" ); document.write( "
Algebra.Com's Answer #2355 by Abbey(339)\"\" \"About 
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Let the cost of apples be x
\n" ); document.write( "Let the cost of oranges be y
\n" ); document.write( "Then:
\n" ); document.write( "6x+3y=3.36
\n" ); document.write( "2x+5y=3.04 \r
\n" ); document.write( "\n" ); document.write( "Multiply the first equation by -1/3
\n" ); document.write( "-2x+-y=-1.12
\n" ); document.write( "2x+5y=3.04 \r
\n" ); document.write( "\n" ); document.write( "add the second equation to the first
\n" ); document.write( "4y=1.92\r
\n" ); document.write( "\n" ); document.write( "divide both sides by 4
\n" ); document.write( "y=.48
\n" ); document.write( "put this back into either of the original equations to find out how much an apples costs
\n" ); document.write( "6x+3y=3.36
\n" ); document.write( "6x+3(.48)=3.36
\n" ); document.write( "6x+1.44=3.36
\n" ); document.write( "6x=3.36-1.44
\n" ); document.write( "6x=2.92
\n" ); document.write( "x=.32\r
\n" ); document.write( "\n" ); document.write( "check this answer by using the other equation:
\n" ); document.write( "2x+5y=3.04
\n" ); document.write( "2(.32)+5(.48)=3.04
\n" ); document.write( ".64+2.40=3.04
\n" ); document.write( "This is true, so oranges cost .48 cents each and apples cost .32 cents each.\r
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