document.write( "Question 328712: the cost for the manufacturing of a cd varies inversely with the number of cd's made. if the cost is $2.50 per cd when 10,000 are made, then what is the cost per cd when 100,000 are made? \n" ); document.write( "
Algebra.Com's Answer #235479 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula for inverse variation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = k/x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k is the constant of variation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let y = cost per cd \n" ); document.write( "let x = number of cd\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = k/x becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2.50 = k / 10,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for k to get k = 10,000 * 2.50 = 25,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since k is a constant, it will not change.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cost when 100,000 cd are made would therefore be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 25,000 / 100,000 = .25 per cd. \n" ); document.write( " \n" ); document.write( " |