document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38049>Question 38049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the SLOPE of <BR>\n" );
document.write( "a. (8,3), (-4,3)<BR>\n" );
document.write( "b. (9,-2), (3,4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23547 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the slope formula<BR>\n" );
document.write( "m = (y2 - y1) / (x2 - x1)<BR>\n" );
document.write( "for the first pair we have<BR>\n" );
document.write( "m = (3 - 3) / (-4 - 8) = 0<BR>\n" );
document.write( "and for the second<BR>\n" );
document.write( "m = (4 - -2) / (3 - 9) = 6 / -6 = -1 </SPAN>\n" );
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