document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328658>Question 328658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one circle is circumscribed around a square that has sides of length 2. Another circle is inscribed in the same square.<BR>\n" );
document.write( "Find the ratio of the area of the larger circle to that of the smaller circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235442 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square circumscribed by a circle<BR>\n" );
document.write( "length of square = 2<BR>\n" );
document.write( "so diagonal = 2sqrt2<BR>\n" );
document.write( "1/2 diameter = 1/2 * 2sqrt2<BR>\n" );
document.write( "radius = sqrt2<BR>\n" );
document.write( "area of circle = pi*(sqt2)^2<BR>\n" );
document.write( "area = 2pi<BR>\n" );
document.write( "..<BR>\n" );
document.write( "circle circumscribed in a square<BR>\n" );
document.write( "1/2 diagonal of square = sqrt2<BR>\n" );
document.write( "1/2 the side = 1<BR>\n" );
document.write( "(sqrt2)^2-1^2= radius of cicle ^2<BR>\n" );
document.write( "2-1=radius squared<BR>\n" );
document.write( "1 = radius<BR>\n" );
document.write( "area of circle = pi*1^2<BR>\n" );
document.write( "=pi\r<BR>\n" );
document.write( "\n" );
document.write( "ratio = 2pi/pi<BR>\n" );
document.write( "=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );