document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328449>Question 328449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes a station at 3:10 A.M. If train B passes the same station at 3:25 A.M, at what time will train B catch  up to train A??\r<BR>\n" );
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document.write( "When will train B catch up to train A??  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235402 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=rt<BR>\n" );
document.write( "Train a: d=40t<BR>\n" );
document.write( "Train b: d=48(t-.25)<BR>\n" );
document.write( "40t=48(t-.25)<BR>\n" );
document.write( "40t=48t-12<BR>\n" );
document.write( "40t-48t=-12<BR>\n" );
document.write( "-8=-12<BR>\n" );
document.write( "t=-12/-8<BR>\n" );
document.write( "t=1.5 hours after 3:10 they will meet.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "40*1.5=48(1.5-.25)<BR>\n" );
document.write( "60=48*1.25<BR>\n" );
document.write( "60=60 </SPAN>\n" );
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