document.write( "Question 4850: Six apples and three oranges cost $3.36. Two apples and five oranges cost $3.04. Find the cost of an apple and the cost of an orange. \n" ); document.write( "
Algebra.Com's Answer #2354 by rapaljer(4671)\"\" \"About 
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Let x = number of apples
\n" ); document.write( "y = number of oranges\r
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\n" ); document.write( "\n" ); document.write( "6x + 3y = $3.36
\n" ); document.write( "2x + 5y = $3.04\r
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\n" ); document.write( "\n" ); document.write( "The easiest way to eliminate a variable is to multiply both sides of the second equation by -3.\r
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\n" ); document.write( "\n" ); document.write( "6x + 3y = $3.36
\n" ); document.write( "-3(2x + 5y) = -3($3.04)\r
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\n" ); document.write( "\n" ); document.write( "6x + 3y = $3.36
\n" ); document.write( "-6x - 15y = -9.12\r
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\n" ); document.write( "\n" ); document.write( "Add the equations together:
\n" ); document.write( "-12y = -5.76\r
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\n" ); document.write( "\n" ); document.write( "Divide by -12, and get y = $.48 per orange\r
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\n" ); document.write( "\n" ); document.write( "Substitute y = .48
\n" ); document.write( "6x + 3y = $3.36
\n" ); document.write( "6x + 3(.48) = 3.36
\n" ); document.write( "6x + 1.44 = 3.36
\n" ); document.write( "6x = 1.92
\n" ); document.write( "x = $.32 per apple\r
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\n" ); document.write( "\n" ); document.write( "Check both numbers in the second equation:
\n" ); document.write( "2x + 5y = $3.04
\n" ); document.write( "2(.32) + 5(.48) = 3.04
\n" ); document.write( "$.64 + $2.40 = $3.04\r
\n" ); document.write( "\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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