document.write( "Question 328581: Extreme hardship. Kim starts to walk 3 mi to school at
\n" ); document.write( "7:30 A.M. with a temperature of 0°F. Her brother Bryan
\n" ); document.write( "starts at 7:40 A.M. on his bicycle, traveling 10 mph faster
\n" ); document.write( "than Kim. If they get to school at the same time, then how
\n" ); document.write( "fast is each one traveling?
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Algebra.Com's Answer #235394 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Kim starts to walk 3 mi to school at
\n" ); document.write( "7:30 A.M. with a temperature of 0°F. Her brother Bryan
\n" ); document.write( "starts at 7:40 A.M. on his bicycle, traveling 10 mph faster
\n" ); document.write( "than Kim. If they get to school at the same time, then how
\n" ); document.write( "fast is each one traveling?
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\n" ); document.write( "Kim DATA:
\n" ); document.write( "distance = 3 mi ; rate = x mph ; time = 3/x hrs
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\n" ); document.write( "Bryan DATA:
\n" ); document.write( "distance = 3 mi ; rate = x+10 mph ; tim = 3/(x+10)
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\n" ); document.write( "Equation:
\n" ); document.write( "Kim time - Bryan time = 1/6 hr
\n" ); document.write( "3/x - 3/(x+10) = 1/6
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\n" ); document.write( "Multiply thru by 6x(x+10) to get:
\n" ); document.write( "18(x+10) - 18x = x(x+10)
\n" ); document.write( "180 = x^2+10x
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\n" ); document.write( "x^2+10x-180 = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = [-10+sqrt(100-4*-180]/2
\n" ); document.write( "x = 9.32 mph (Kim speed)
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\n" ); document.write( "x+10 = 19.32 mph (Bryan speed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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