document.write( "Question 328458: During the first part of a trip, a canoeist travels 76 miles at a certain speed. The canoeist travels 2 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 3 hours. What was the speed on each part of the trip?\r
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document.write( "(type an integer or a decimal. Round to the nearest hundredth) \n" );
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Algebra.Com's Answer #235393 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "FOR THE FIRST PART OF THE TRIP; \n" ); document.write( "76=RT \n" ); document.write( "T=76/R \n" ); document.write( "FOR THE SECOND PART OF THE TRIP: \n" ); document.write( "2=(R-6)T \n" ); document.write( "T=2/(R-6) \n" ); document.write( "76/R+2/(R-6)=3 \n" ); document.write( "(76(R-6)+2R)/R(R-6)=3 \n" ); document.write( "(76R-456+2R)/(R^2-6R)=3 \n" ); document.write( "(78R-456)/(R^2-6R)=3 CROSS MULTIPLY. \n" ); document.write( "78R-456=3(R^2-6R) \n" ); document.write( "78R-456=3R^2-18R \n" ); document.write( "3R^2-18R-78R+456=0 \n" ); document.write( "3R^2-96R+456=0 \n" ); document.write( "3(R^2-32R+152)=0 \n" ); document.write( " \n" ); document.write( "R=(32+-SQRT(32^2-4*1*152])/2*1 \n" ); document.write( "R=(32+-SQRT[1,024-608])/2 \n" ); document.write( "R=(32+-SQRT416)/2 \n" ); document.write( "R=(32+-20.396)/2 \n" ); document.write( "R=(32+20.396)/2 \n" ); document.write( "R=52.396/2 \n" ); document.write( "R=26.198 MPH. ANS. \n" ); document.write( "PROOF: \n" ); document.write( "76/26.198+2/(26.198-6)=3 \n" ); document.write( "2.9+2/20.198=3 \n" ); document.write( "2.9+.1=3 \n" ); document.write( "3=3 \n" ); document.write( " |