document.write( "Question 328580: Stumped once again!!!\r
\n" ); document.write( "\n" ); document.write( "2x^2-5x-2 =0\r
\n" ); document.write( "\n" ); document.write( "How is the quadratic formula used to solve this equation? Anyone know?
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Algebra.Com's Answer #235391 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The quadratic formula for finding roots is
\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "You need to know what a, b, and c refer to
\n" ); document.write( "This formula assumes that the equation is in the form
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
\n" ); document.write( "Your equation is already in this form:
\n" ); document.write( "\"2x%5E2-5x-2+=0\"
\n" ); document.write( "\"a+=+2\"
\n" ); document.write( "\"b+=+-5\"
\n" ); document.write( "\"c+=+-2\"
\n" ); document.write( "plugging in the numbers:
\n" ); document.write( " \"x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%2A2%2A%28-2%29+%29%29%2F%282%2A2%29+\"
\n" ); document.write( " \"x+=+%285+%2B-+sqrt%28+25+%2B+16+%29%29%2F4+\"
\n" ); document.write( "\"x+=+%285+%2B-+sqrt%2841%29%29%2F4\"
\n" ); document.write( "I'm guessing that \"c\" should be \"2\" and not \"-2\". That would make the
\n" ); document.write( "solution
\n" ); document.write( "\"x+=+%285+%2B-+sqrt%2825+-+16%29%29%2F4\"
\n" ); document.write( "\"x+=+%285+%2B-+sqrt%289%29%29%2F4\"
\n" ); document.write( "\"x+=+%285+%2B+3%29%2F4\"
\n" ); document.write( "\"x+=+2\"
\n" ); document.write( "and
\n" ); document.write( "\"x+=+%285+-+3%29%2F4\"
\n" ); document.write( "\"x+=+1%2F2\"
\n" ); document.write( "These are the 2 roots.
\n" ); document.write( "If \"c+=+-2\" for real, then stick with \"x+=+%285+%2B-+sqrt%2841%29%29%2F4\"
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