document.write( "Question 328296: The chief of police for smalltown USA notice that, not including himself, 3/5 of his police force carries firearms.\r
\n" ); document.write( "\n" ); document.write( "If he include himself, 5/8 of his force carries fairearms. How many people on his force do not carry firearms?\r
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\n" ); document.write( "\n" ); document.write( "a) 5\r
\n" ); document.write( "\n" ); document.write( "b) 6\r
\n" ); document.write( "\n" ); document.write( "c) 11\r
\n" ); document.write( "\n" ); document.write( "d) 16\r
\n" ); document.write( "\n" ); document.write( "e) 24
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Algebra.Com's Answer #235368 by ankor@dixie-net.com(22740)\"\" \"About 
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The chief of police for small town USA notice that, not including himself,
\n" ); document.write( " 3/5 of his police force carries firearms.
\n" ); document.write( "If he include himself, 5/8 of his force carries firearms.
\n" ); document.write( " How many people on his force do not carry firearms?
\n" ); document.write( ":
\n" ); document.write( "Originally then, 2/5 did not carry guns
\n" ); document.write( "Later then, 3/8 did not carry guns
\n" ); document.write( ":
\n" ); document.write( "Let x = total on the police force not counting the chief
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\n" ); document.write( "No. not carrying guns remains unchanged, so we have:
\n" ); document.write( "\"2%2F5\"x = \"3%2F8\"(x+1)
\n" ); document.write( "Multiply both sides by 40, results
\n" ); document.write( "8(2)x = 5(3(x+1))
\n" ); document.write( "16x = 15x + 15
\n" ); document.write( "16x - 15x = 15
\n" ); document.write( "x = 15 total on the police force
\n" ); document.write( "then
\n" ); document.write( "\"2%2F5\"*15 = 6 did not carry guns
\n" ); document.write( ":
\n" ); document.write( "Confirm solution
\n" ); document.write( "\"3%2F8\"*(15+1) = 6 also
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