document.write( "Question 328488: The perimeter of a basketball court is 284 ft. the length is 40 ft. longer than the width. What are the dimensions of the court
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Algebra.Com's Answer #235365 by checkley77(12844)\"\" \"About 
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L=W+40
\n" ); document.write( "P=2L+2W
\n" ); document.write( "284=2(W+40)2W
\n" ); document.write( "284=2W+80+2W
\n" ); document.write( "4W=284-80
\n" ); document.write( "4W=204
\n" ); document.write( "W=204/4
\n" ); document.write( "W=51 FT.
\n" ); document.write( "L=51+40=91 FT.
\n" ); document.write( "PROOF:
\n" ); document.write( "284=2*91+2*51
\n" ); document.write( "284=182+102
\n" ); document.write( "284=284
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