document.write( "Question 328488: The perimeter of a basketball court is 284 ft. the length is 40 ft. longer than the width. What are the dimensions of the court
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Algebra.Com's Answer #235365 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+40 \n" ); document.write( "P=2L+2W \n" ); document.write( "284=2(W+40)2W \n" ); document.write( "284=2W+80+2W \n" ); document.write( "4W=284-80 \n" ); document.write( "4W=204 \n" ); document.write( "W=204/4 \n" ); document.write( "W=51 FT. \n" ); document.write( "L=51+40=91 FT. \n" ); document.write( "PROOF: \n" ); document.write( "284=2*91+2*51 \n" ); document.write( "284=182+102 \n" ); document.write( "284=284 \n" ); document.write( " |