document.write( "Question 328415: chad drove 3 times as fast as katy pedaled. I fact, chad drove 90 miles in 2 hrs less than it took katy to pedal 40 miles. How fast did each of them travel. How long did they travel? \n" ); document.write( "

Algebra.Com's Answer #235350 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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chad drove 3 times as fast as katy pedaled.
\n" ); document.write( "In fact, chad drove 90 miles in 2 hrs less than it took katy to pedal 40 miles.
\n" ); document.write( " How fast did each of them travel. How long did they travel?
\n" ); document.write( ":
\n" ); document.write( "Let s = K's speed
\n" ); document.write( "then
\n" ); document.write( "3s = C's speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "K's time - C's time = 2 hrs
\n" ); document.write( " $\"40%2Fs\"$ - $\"90%2F%283s%29\"$ = 2
\n" ); document.write( "Reduce fraction
\n" ); document.write( " $\"40%2Fs\"$ - $\"30%2Fs\"$ = 2
\n" ); document.write( " $\"10%2Fs\"$ = 2
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( "10 = 2s
\n" ); document.write( "s = $\"10%2F2\"$
\n" ); document.write( "s = 5 mph is K's speed
\n" ); document.write( "then
\n" ); document.write( "2(5) = 15 mph is C's speed
\n" ); document.write( ":
\n" ); document.write( "Find the travel times
\n" ); document.write( "90/15 = 6 hrs
\n" ); document.write( "40/5 = 8 hrs
\n" ); document.write( "--------------
\n" ); document.write( "diff: 2 hrs, confirms our solutions
\n" ); document.write( " \n" ); document.write( "

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