document.write( "Question 328538: a manufacturer plans to spend $150,000 on research and development for a new lawn mower and then $200 to manufacture each mower. the formula C=200n+150,000 gives the cost in dollars of n mowers. what is the cost of 5000 mowers?
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document.write( "what is the cost of 5001 mowers?
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document.write( "by how much did the one extra mower increase the cost? \n" );
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Algebra.Com's Answer #235347 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! C = 200n + 150,000\r \n" ); document.write( "\n" ); document.write( "Let n = 5000\r \n" ); document.write( "\n" ); document.write( "C = 200(5000) + 150,000\r \n" ); document.write( "\n" ); document.write( "C = $1,150,000\r \n" ); document.write( "\n" ); document.write( "We now do the same thing for n = 5001 and solve for C.\r \n" ); document.write( "\n" ); document.write( "C = 200(5001) + 150,000\r \n" ); document.write( "\n" ); document.write( "C = $1,150,200\r \n" ); document.write( "\n" ); document.write( "Let E = money that extra mover increased the cost\r \n" ); document.write( "\n" ); document.write( "E = 1,150,200 - 1,150,000\r \n" ); document.write( "\n" ); document.write( "E = $1,000,200\r \n" ); document.write( "\n" ); document.write( "I hope this helps.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |