document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328543>Question 328543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangle RST, RS= 2x+10, ST = 3x-2 and  RT = (1/2)x +28. if triangle is equiangular, what is the value of x ?\r<BR>\n" );
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document.write( "A  2  B  5 1/3  C  6  D  12  E  34 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235344 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the triangle is equiangular, then all sides must be the same length.\r<BR>\n" );
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document.write( "Equate any two sides that you like and solve for x.\r<BR>\n" );
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document.write( "I will equate 2x + 10 to 3x - 2.\r<BR>\n" );
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document.write( "2x + 10 = 3x - 2\r<BR>\n" );
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document.write( "2x - 3x = -2 - 10\r<BR>\n" );
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document.write( "-x = -12\r<BR>\n" );
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document.write( "x = -12/-1\r<BR>\n" );
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document.write( "x = 12\r<BR>\n" );
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document.write( "CHOICE D is correct. </SPAN>\n" );
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