document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328496>Question 328496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A missile is launched and travels along a path that can be represented by:\r<BR>\n" );
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document.write( "		y= the Square root of X	 \r<BR>\n" );
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document.write( "A radar tracking station is located 2 km directly behind the launch pad. Placing the launch pad at the origin and the radar station at (-2, 0), find the largest angle of elevation required of the radar to track the missile<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235297 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The max angle will be attained by the tangent line to the curve y=sqrt(x) that passes through x=-2.  The thing is, we have to find this point on the curve.\r<BR>\n" );
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document.write( "We can do this by using the equation of a line formula.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-y1=m%28x-x1%29 ALIGN=MIDDLE  ALT=\"y-y1=m%28x-x1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "y1=0, x1=-2, y=sqrt(x), m=1/(2*sqrt(x))\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%29-0=1%2F%282%2Asqrt%28x%29%29%2A%28x%2B2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%29-0=1%2F%282%2Asqrt%28x%29%29%2A%28x%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solving for x, we find x=2.\r<BR>\n" );
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document.write( "The line is tangent to the curve at (2,sqrt(2)).\r<BR>\n" );
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document.write( "By the law of tangents, we can easily find the angle now.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=arctan%28sqrt%282%29%2F4%29=19.4712206345 ALIGN=MIDDLE  ALT=\"arctan%28sqrt%282%29%2F4%29=19.4712206345\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees is the max angle. </SPAN>\n" );
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