document.write( "Question 328408: A production line manufactures 5-gal(18.93-liter) gasoline cans to a volume tolerance of 5%. The probability of any one can being out of tolerance is 0.03. If 4 cans are selected at random:
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document.write( "a)What is the probability they are all out of tolerance?
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document.write( "b)What is the probability of exactly two being out?
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document.write( "c)What is the probability that all are in tolerance? \n" );
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Algebra.Com's Answer #235267 by Fombitz(32388) You can put this solution on YOUR website! a) P(4 bad)= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "b) P(4 good)= \n" ); document.write( "Look at all of the possible combinations of exactly 2 bad (G-good, B-bad) \n" ); document.write( "GGBB \n" ); document.write( "GBGB \n" ); document.write( "GBBG \n" ); document.write( "BGGB \n" ); document.write( "BGBG \n" ); document.write( "BBGG \n" ); document.write( "There are 6 of them. \n" ); document.write( "Their individual probabilities are \n" ); document.write( "Since there are 6 of them, \n" ); document.write( "P(exactly 2 bad)= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "c) P(4 good)= \n" ); document.write( " \n" ); document.write( " |