document.write( "Question 328408: A production line manufactures 5-gal(18.93-liter) gasoline cans to a volume tolerance of 5%. The probability of any one can being out of tolerance is 0.03. If 4 cans are selected at random:
\n" ); document.write( "a)What is the probability they are all out of tolerance?
\n" ); document.write( "b)What is the probability of exactly two being out?
\n" ); document.write( "c)What is the probability that all are in tolerance?
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Algebra.Com's Answer #235267 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) P(4 bad)=\"%280.03%29%280.03%29%280.03%29%280.03%29=8.1x10%5E%28-7%29\"
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\n" ); document.write( "b) P(4 good)=\"%280.97%29%5E4=0.8853\"
\n" ); document.write( "Look at all of the possible combinations of exactly 2 bad (G-good, B-bad)
\n" ); document.write( "GGBB
\n" ); document.write( "GBGB
\n" ); document.write( "GBBG
\n" ); document.write( "BGGB
\n" ); document.write( "BGBG
\n" ); document.write( "BBGG
\n" ); document.write( "There are 6 of them.
\n" ); document.write( "Their individual probabilities are \"P=%280.97%29%5E2%280.03%29%5E2=0.00084681\"
\n" ); document.write( "Since there are 6 of them,
\n" ); document.write( "P(exactly 2 bad)=\"6%280.00084681%29=0.00508\"
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\n" ); document.write( "c) P(4 good)=\"%280.97%29%5E4=0.8853\"
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