document.write( "Question 328453: find the sum of the series 5/13 + 55/(13)^2 + 555/(13)^3 + ... \n" ); document.write( "
Algebra.Com's Answer #235265 by galactus(183)\"\" \"About 
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This is kind of tricky trying to set up a general form for 5,55,555,....\r
\n" ); document.write( "\n" ); document.write( "We can think of the numerators: 5,55,555,5555,...., as\r
\n" ); document.write( "\n" ); document.write( "\"%285%2F9%29%2810%5En-1%29\"\r
\n" ); document.write( "\n" ); document.write( "But, this gives us a general form of\r
\n" ); document.write( "\n" ); document.write( "\"%285%2F9%29%2Asum%28%2810%5En-1%29%2F13%5En%2Cn=1%2Cinfinity%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using the formula for the sum of an infinite series we get \r
\n" ); document.write( "\n" ); document.write( "\"%2810%2F13%29%2F%281-10%2F13%29=10%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F13%29%2F%281-1%2F13%29=1%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"5%2F9%2A%2810%2F3-1%2F12%29=65%2F36\"\r
\n" ); document.write( "\n" ); document.write( "The sum is 65/36
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