document.write( "Question 328423: A missile can be accidentally launched if two relays A and B both have failed. the probabilities of A and B failing known to be 0.01 and 0.03 respectively. It is also known that B is more likely to fail(probability 0.06) if A has failed.
\n" ); document.write( "a)What is the probability of an accidental missile launch?
\n" ); document.write( "b)What is the probability that A will fail if B has failed?
\n" ); document.write( "c)Are the events \"A fails\" and \"B fails\" statistically independent?
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Algebra.Com's Answer #235250 by galactus(183)\"\" \"About 
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Probability B fails given A fails, P(B|A), is given as .06\r
\n" ); document.write( "\n" ); document.write( "P(A)=.01\r
\n" ); document.write( "\n" ); document.write( "P(B)=.03\r
\n" ); document.write( "\n" ); document.write( "part a would be the probability A and B fail, P(A and B)\r
\n" ); document.write( "\n" ); document.write( "P(B|A)=P(A and B)/P(A)\r
\n" ); document.write( "\n" ); document.write( ".06=P(A and B)/.01\r
\n" ); document.write( "\n" ); document.write( "P(A and B)=.0006\r
\n" ); document.write( "\n" ); document.write( "part b, P(A|B)=P(A and B)/P(B)\r
\n" ); document.write( "\n" ); document.write( "We now have P(A and B)=.0006 from part a. Use this to answer part b.\r
\n" ); document.write( "\n" ); document.write( "P(A|B)=.0006/.03=.02\r
\n" ); document.write( "\n" ); document.write( "part c, the events are independent if the occurence of one does not affect the occurence of the other. That is, if P(B|A)=P(B) or P(A|B)=P(A) they are independent.\r
\n" ); document.write( "\n" ); document.write( "Are they the same?.
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