document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38023>Question 38023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the polynomial function f(x)=x^3+x^2-5x-6 has a zero at x=-2.that implies that x+2 must be a factor of the polynomial. find the other factors by either polynomial long division, or synthetic division...i really dont mind which process you choose, i just need help grasping these concepts. id say im more familiar with polynomial long division. this is part of a take home extra credit assignment i was given, so i dont have any book info, thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23522 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=x^3+x^2-5x-6 has a zero at x=-2\r<BR>\n" );
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document.write( "Use your long division.<BR>\n" );
document.write( "Divide f(x) by x+2 and you will get a <BR>\n" );
document.write( "quotient of x^2-x-3 and with a remainder<BR>\n" );
document.write( "of zero.<BR>\n" );
document.write( "Now solve the quotient for x by using the<BR>\n" );
document.write( "quadratic formula, as follows:<BR>\n" );
document.write( "x=[1+sqrt(1+12)]/2=[1+-sqrt(13)]/2<BR>\n" );
document.write( "This means the other two factors are:<BR>\n" );
document.write( "(x-[(1/2)+(1/2)sqrt13]) and (x-[(1/2)-(1/2)sqrt13])<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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