document.write( "Question 328385: a long distance trucker travled 220 miles in one direction during a snow storm. The return trip in a rainy weather was accomplished at doubled the speed and took 5 hours less time. find the speed going. \n" ); document.write( "
Algebra.Com's Answer #235219 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
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\n" ); document.write( "\"R1%2AT1=220\"
\n" ); document.write( "\"R2%2AT2=220\"
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\n" ); document.write( "\"R2=2%2AR1\"
\n" ); document.write( "\"T2=T1-5\"
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\n" ); document.write( "1.\"R1%2AT1=220\"
\n" ); document.write( "2.\"2R1%2A%28T1-5%29=220\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"T1=220%2FR1\"
\n" ); document.write( "Substituting into eq. 2,
\n" ); document.write( "\"2R1%2A%28%28220%2FR1%29-5%29=220\"
\n" ); document.write( "\"440-10R1=220\"
\n" ); document.write( "\"-10R1=-220\"
\n" ); document.write( "\"highlight%28R1=22%29\"mph
\n" ); document.write( "Then from above,
\n" ); document.write( "\"R2=44\"mph
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