document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328371>Question 328371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rice dealer mixes two varieties of rice, one that sells at P500 a sack and anotherat P520 a sack.  He intends to fill up 100 sacks to be sold at P515 each. How many sacks of rice each variety are needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235194 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of P500 sacks he mixes be x<BR>\n" );
document.write( "the P520 he mixes will be 100-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "mixture P515 100 bags<BR>\n" );
document.write( "500x+520(100-x)=515*100<BR>\n" );
document.write( "500x+52000-520x=51500<BR>\n" );
document.write( "-20x=51500-52000<BR>\n" );
document.write( "-20x=-500<BR>\n" );
document.write( "x=-500/-20<BR>\n" );
document.write( "x=25 -------- the p500 type<BR>\n" );
document.write( "balance 75 will be P520 type sacks </SPAN>\n" );
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