document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328276>Question 328276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder is resting against a wall. The top of the ladder touches the wall at a height of 6 ft. Find the length of the ladder if the length is 2 feet more than its distance from the wall. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235168 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the distance of the foot of the ladder to the wall be x feet<BR>\n" );
document.write( "length of ladder = x+2<BR>\n" );
document.write( "height at which it touches the wall = 6 feet<BR>\n" );
document.write( "They form a right triangle<BR>\n" );
document.write( "(x+2)^2= x^2+6^2<BR>\n" );
document.write( "x^2+4x+4=x^2+36 ( x^2 cancels off)<BR>\n" );
document.write( "4x+4=36<BR>\n" );
document.write( "4x=36-4<BR>\n" );
document.write( "4x=32<BR>\n" );
document.write( "x=32/8<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "x+2 = 8+2 = 10 feet is the length of the ladder. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );