document.write( "Question 328320: solve by the addition method:\r
\n" ); document.write( "\n" ); document.write( "(x/4) - (y-3) = -4 and (x/8) + (y/6) = 0 \n" ); document.write( "
Algebra.Com's Answer #235140 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
(x/4) - (y-3) = -4
\n" ); document.write( "LCM = 4
\n" ); document.write( "x-4(y-3) / 4 =-4
\n" ); document.write( "x-4y+12 / 4 =-4
\n" ); document.write( "x-4y+12=-16
\n" ); document.write( "x-4y=-16-12
\n" ); document.write( "x-4y=-28...................1
\n" ); document.write( "(x/8) + (y/6) = 0
\n" ); document.write( "LCM 24
\n" ); document.write( "3x+4y /24 =0
\n" ); document.write( "3x+4y=0....................2
\n" ); document.write( "Add equation1 & 2
\n" ); document.write( "x-4y+3x+4y=-28
\n" ); document.write( "4x=-28
\n" ); document.write( "divide by4
\n" ); document.write( "4x/4=-28/4
\n" ); document.write( "x=-7
\n" ); document.write( "..
\n" ); document.write( "plug the value of x in equation 1
\n" ); document.write( "-7-4y=-28
\n" ); document.write( "-4y=-28+7
\n" ); document.write( "-4y=-21
\n" ); document.write( "divide by -4
\n" ); document.write( "y=21/4
\n" ); document.write( " \n" ); document.write( "
\n" );