document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328330>Question 328330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using substitution<BR>\n" );
document.write( "3x+2y=6<BR>\n" );
document.write( "x=34-6y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235133 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+2y=6<BR>\n" );
document.write( "x=34-6y<BR>\n" );
document.write( "..<BR>\n" );
document.write( "plug the value of x in the first equation<BR>\n" );
document.write( "3(34-6y)+2y=6<BR>\n" );
document.write( "102-18y+2y=6<BR>\n" );
document.write( "-16y=-102+6<BR>\n" );
document.write( "-16y=-96<BR>\n" );
document.write( "y=-96/-16<BR>\n" );
document.write( "y=6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "plug the value of y in the same equation<BR>\n" );
document.write( "3x+2*6=6<BR>\n" );
document.write( "3x+12=6<BR>\n" );
document.write( "3x=-12+6<BR>\n" );
document.write( "3x=-6<BR>\n" );
document.write( "x=-4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );