document.write( "Question 328135: The question is: The perimeter of a rectangle is 96 meters. Three times the width is 8 meters less than the length. What are the dimensions of the rectangle?
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document.write( "A) Identify the two unknowns:
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document.write( "B) Write a system using the two unknowns:
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document.write( "C) Solve the system using any (Substitution, Elimination) method\r
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document.write( "I know that \"Three times\" is the same as saying 3x also that \"the width is 8 meters less then the length\" is the same as saying W=8-L. I know that P (Perimeter) is 96 meters. I just don't know how to solve for the rest of the problem!
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Algebra.Com's Answer #235087 by edjones(8007) You can put this solution on YOUR website! Comment: W=8-L is not the same as W=L-8 \n" ); document.write( ". \n" ); document.write( "Let L=length, w=width and P=perimeter \n" ); document.write( "2L+2w=P \n" ); document.write( "2L+2w=96 \n" ); document.write( ". \n" ); document.write( "3w=L-8 \n" ); document.write( "L=3w+8 \n" ); document.write( ". \n" ); document.write( "2(3w+8)+2w=96 Substitution \n" ); document.write( "6w+16+2w=96 \n" ); document.write( "8w=80 \n" ); document.write( "w=10 m \n" ); document.write( "L=38 m \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |