document.write( "Question 328191: If an object is propelled upward from a height of 96ft at an initial velocity of 80ft per second, then its height after t seconds is given by the equation h = -16t^2 + 80t + 96 where h is in feet. After how many seconds will the object reach a height of 196ft?\r
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Algebra.Com's Answer #235072 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! an object is propelled upward from a height of 96ft at an initial velocity of 80ft per second, \n" ); document.write( "its height after t seconds is given by the equation h = -16t^2 + 80t + 96 where h is in feet. \n" ); document.write( " After how many seconds will the object reach a height of 196ft? \n" ); document.write( ": \n" ); document.write( "-16t^2 + 80t + 96 = h \n" ); document.write( "Replace h with 196 \n" ); document.write( "-16t^2 + 80t + 96 = 196 \n" ); document.write( "-16t^2 + 80t + 96 - 196 = 0 \n" ); document.write( "-16t^2 + 80t - 100 = 0 \n" ); document.write( "Simplify & change the signs, divide by -4, (easier to factor) \n" ); document.write( "4t^2 - 20x + 25 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(2t-5)(2t-5) = 0 \n" ); document.write( "2t = 5 \n" ); document.write( "t = \n" ); document.write( "t = 2.5 seconds it will be 196 ft (this is also the max height) \n" ); document.write( ": \n" ); document.write( "Graphically; t on the x axis, h on the y axis \n" ); document.write( " |