document.write( "Question 328191: If an object is propelled upward from a height of 96ft at an initial velocity of 80ft per second, then its height after t seconds is given by the equation h = -16t^2 + 80t + 96 where h is in feet. After how many seconds will the object reach a height of 196ft?\r
\n" ); document.write( "\n" ); document.write( " I am not so good at word problems and am really confused! You have great tutors that I appreciate so very much. I hope that someone will lend me a hand this one has me stumped. Thank you in advance.
\n" ); document.write( "

Algebra.Com's Answer #235072 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
an object is propelled upward from a height of 96ft at an initial velocity of 80ft per second,
\n" ); document.write( "its height after t seconds is given by the equation h = -16t^2 + 80t + 96 where h is in feet.
\n" ); document.write( " After how many seconds will the object reach a height of 196ft?
\n" ); document.write( ":
\n" ); document.write( "-16t^2 + 80t + 96 = h
\n" ); document.write( "Replace h with 196
\n" ); document.write( "-16t^2 + 80t + 96 = 196
\n" ); document.write( "-16t^2 + 80t + 96 - 196 = 0
\n" ); document.write( "-16t^2 + 80t - 100 = 0
\n" ); document.write( "Simplify & change the signs, divide by -4, (easier to factor)
\n" ); document.write( "4t^2 - 20x + 25 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(2t-5)(2t-5) = 0
\n" ); document.write( "2t = 5
\n" ); document.write( "t = \"5%2F2\"
\n" ); document.write( "t = 2.5 seconds it will be 196 ft (this is also the max height)
\n" ); document.write( ":
\n" ); document.write( "Graphically; t on the x axis, h on the y axis
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+8%2C+-100%2C+240%2C+-16x%5E2%2B80x%2B96%29+\"
\n" ); document.write( "
\n" );