document.write( "Question 328059: find all t in the interval [0,2pi] satisfying sin x - cos x = 1. I do not know where to start with this \n" ); document.write( "
Algebra.Com's Answer #235018 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use the trig identitites along with your equation.
\n" ); document.write( "\"sin%28x%29-cos%28x%29=1\"
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\n" ); document.write( "\"sin%28x%29=cos%28x%29%2B1\"
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\n" ); document.write( "\"sin%5E2%28x%29=%28cos%28x%29%2B1%29%5E2\"
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\n" ); document.write( "\"1-cos%5E2%28x%29=cos%5E2%28x%29%2B2cos%28x%29%2B1\"
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\n" ); document.write( "\"2cos%5E2%28x%29%2B2cos%28x%29=0\"
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\n" ); document.write( "\"cos%28x%29%28cos%28x%29%2B1%29=0\"
\n" ); document.write( "Two solutions from the zero product property:
\n" ); document.write( "\"cos%28x%29=0\"
\n" ); document.write( "\"x=pi%2F2\" and \"x=%283pi%29%2F2\"
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\n" ); document.write( "\"cos%28x%29%2B1=0\"
\n" ); document.write( "\"cos%28x%29=-1\"
\n" ); document.write( "\"x=pi\"
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\n" ); document.write( "Verify the solutions.
\n" ); document.write( "\"sin%28x%29-cos%28x%29=1\"
\n" ); document.write( "\"sin%28pi%29-cos%28pi%29=1\"
\n" ); document.write( "\"0-%28-1%29=1\"
\n" ); document.write( "\"1=1\"
\n" ); document.write( "\"x=pi\" is a valid solution.
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\n" ); document.write( "\"sin%28x%29-cos%28x%29=1\"
\n" ); document.write( "\"sin%28pi%2F2%29-cos%28pi%2F2%29=1\"
\n" ); document.write( "\"1-0=1\"
\n" ); document.write( "\"1=1\"
\n" ); document.write( "\"x=pi%2F2\" is a valid solution.
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\n" ); document.write( "\"sin%28x%29-cos%28x%29=1\"
\n" ); document.write( "\"sin%28%283pi%29%2F2%29-cos%28%283pi%29%2F2%29=1\"
\n" ); document.write( "\"-1-0=1\"
\n" ); document.write( "\"-1=1\"
\n" ); document.write( "\"x=%283pi%29%2F2\" is not a valid solution.
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\n" ); document.write( "Two solution: \"x=pi%2F2\" and \"x=pi\"
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