document.write( "Question 328087: An ellipse with center at the origin and the horizontal major axis is to fit snugly insidde a rectangle that has its longer sides horzontal. The area of the rectangle is 12 square units, and the perimeter is 14 units find an equation for the ellipse. \n" ); document.write( "
Algebra.Com's Answer #235014 by galactus(183)\"\" \"About 
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The rectangle has perimeter 2x+2y=14\r
\n" ); document.write( "\n" ); document.write( "and area xy=12\r
\n" ); document.write( "\n" ); document.write( "Solve area for y and sub into perimeter, y=12/x\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B2%2812%2Fx%29=14\"\r
\n" ); document.write( "\n" ); document.write( "\"x=4\" or \"x=3\"\r
\n" ); document.write( "\n" ); document.write( "x is the longer one, so x=4 and y=3\r
\n" ); document.write( "\n" ); document.write( "This means the semi-major axis has length 2 and the semi-minor axis has length
\n" ); document.write( "3/2\r
\n" ); document.write( "\n" ); document.write( "So, the ellipse equation is \"x%5E2%2F%282%29%5E2%2By%5E2%2F%283%2F2%29%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4%2B4y%5E2%2F9=1\"\r
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