document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=328117>Question 328117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> movie tickets for an adult and three children cost $20. An adult's ticket costs $2 more than a child's ticket. FInd the cost of the adult's ticket. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #235008 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=235008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this problem, you need to write 2 equations using what you know.<BR>\n" );
document.write( "First, you know that movie tickets for an adult and 3 children cost $20. This can be written as:<BR>\n" );
document.write( "A + 3C = 20  (where A = price for an adult ticket, C = price for child's ticket)<BR>\n" );
document.write( "Second, you know that an adult's ticket costs $2 more than a child's ticket:<BR>\n" );
document.write( "A = C + 2<BR>\n" );
document.write( "This can also be written as C = A - 2<BR>\n" );
document.write( "Now plug the second equation into the first and solve for A:<BR>\n" );
document.write( "A + 3C = 20<BR>\n" );
document.write( "A + 3(A - 2) = 20<BR>\n" );
document.write( "A + 3A - 6 = 20<BR>\n" );
document.write( "4A - 6 = 20<BR>\n" );
document.write( "4A = 26<BR>\n" );
document.write( "A = 6.5<BR>\n" );
document.write( "So the price of an adult ticket is $6.50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );