document.write( "Question 327959: An Airline in a small city has 5 departures eachday.It is known that any given flight has a probability of 0.3 of departing late. For any given day find that a)no flights depart late
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document.write( " b)all flights depart late and
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document.write( " c)three or more depart on time \n" );
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Algebra.Com's Answer #234979 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! a) P(All on-time)= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "b) P(All late)= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "c)Look at the outcomes of 2 or fewer late departing flight of the 2^5 possible outcomes (O- on time, L-late).\r \n" ); document.write( "\n" ); document.write( "O O O O O \n" ); document.write( "O O O O L \n" ); document.write( "O O O L O \n" ); document.write( "O O O L L \n" ); document.write( "O O L O O \n" ); document.write( "O O L O L \n" ); document.write( "O O L L O \n" ); document.write( "O L O O O \n" ); document.write( "O L O O L \n" ); document.write( "O L O L O \n" ); document.write( "O L L O O \n" ); document.write( "L O O O O \n" ); document.write( "L O O O L \n" ); document.write( "L O O L O \n" ); document.write( "L O L O O \n" ); document.write( "L L O O O\r \n" ); document.write( "\n" ); document.write( "There are 16 out of 32 possible flights that have 2 or fewer late departing flights. \n" ); document.write( "0 Late=>1 outcome, \n" ); document.write( "1 Late=>5 outcomes, \n" ); document.write( "2 Late=>10 outcomes, \n" ); document.write( "P= |