document.write( "Question 328052: Need Help Please!
\n" ); document.write( "I am failing this class..\r
\n" ); document.write( "\n" ); document.write( "5. Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.\r
\n" ); document.write( "\n" ); document.write( "logx (log3 9) = 2
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Algebra.Com's Answer #234951 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Wow, this looks so confusing, I'm not sure what it says.
\n" ); document.write( "The \"log%283%2C9%29\" is where to start, since it looks simple.
\n" ); document.write( "It says \"I am an exponent to the base \"3\" that gives \"9\"
\n" ); document.write( "I know that \"3%5E2+=+9\", so
\n" ); document.write( "\"log%283%2C9%29+=+2\"
\n" ); document.write( "Now I have
\n" ); document.write( "\"log%28x%2C2%29+=+2\"
\n" ); document.write( "This is saying \"An exponent which is \"2\", with a base that is \"x\"
\n" ); document.write( "gives me \"2\"
\n" ); document.write( "I'll rewrite it as:
\n" ); document.write( "\"x%5E2+=+2\"
\n" ); document.write( "Now take the square root of both sides
\n" ); document.write( "\"x+=+sqrt%282%29\" answer
\n" ); document.write( "and
\n" ); document.write( "\"x+=+-sqrt%282%29\" not answer
\n" ); document.write( "Only the positive result would work here, because what would the
\n" ); document.write( "answer to this be?
\n" ); document.write( "\"log%28-sqrt%282%29%2C+.3027%29\"
\n" ); document.write( "Can't solve it
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